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verify the identify cos(2A)=1-2sin^2(A) using Cos (A+B)=cosA CosB- SinA SinB
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\[\cos2A=\cos(A+A)\]
can u do it further??
expand it
cosA*cosA-sinA*sinA
cos^2A-sin^2A
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cos^2A=1-sin^2A
plug it in place of cos^2A
you lost me at cosA*cosA-sinA*sinA
sum of angles identity is cos (A+B) =cosAcosB-sinAsinB in this case B=A so just sub it in gurl
cos(A+A)=cos ^2 A-sin ^2 A=1-2sin ^2 A since, sin ^2 A+ cos ^2 A=1
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