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solve the identity: sin(x-3pi/2)=cosx
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idk
open the sin
sin(A-B)=sinA*cosB-sinB*cosA
A=x b=3*pi/2
plug in values of A and B
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sin(x)cos(0)-sin(0)0cos(x)
sorry, there's an extra 0
B=3pi/2 not zero
\[sinx*\cos \frac{ 3 *\pi}{ 2 }-\sin \frac{ 3*\pi }{ 2 }*cosx\]
what is cos value at cos(3pi/2)=???
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