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AB ← → and BC ← → form a right angle at point B. If A = (-3, -1) and B = (4, 4), what is the equation of BC ← → ?
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x + 3y = 16 2x + y = 12 -7x − 5y = -48 7x − 5y = 48
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BC is perpendicular to AB
slope of BC = -1/(slope of AB)
slope of AB=(4-(-1))/(4-(-3))
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slope of AB=(4+1)/(4+3)
cal culate this and find slope of BC
and BC pass through (4,4) ....u have one point and slope ..u can do further
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