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(tan70+tan80)/(1-tan70*tan80)
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I think this is the formula for tan(A + B)
\(\bf tan({\color{brown}{ \alpha}} \pm {\color{blue}{ \beta}}) = \cfrac{tan({\color{brown}{ \alpha}})\pm tan({\color{blue}{ \beta}})}{1\mp tan({\color{brown}{ \alpha}})tan({\color{blue}{ \beta}})}\) any ideas?
- if my memory serves me right!
so your expression = tan (70+ 80) = tan 150 degrees
no
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note the tan is negative in the second quadrant
thanks
@cwrw238 Yeah, you're correct. Realized I read the formula wrong. The sign in the fraction should be opposite not the same :P Thx!
(tan(7pi/24)-tan(pi/8))/(1+tan(7pi/24)*tan(pi/8)
yw @Lyrae
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