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Solve. 4(a + 2) = 8 + 4a all real numbers no solution –2 –1
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ok if you distribute 4 you get --> 4a + 8 = 8 + 4a then subtract 4a from both sides and you end up with 8=8...so I think that is all real #'s
After distributing...you'll find that both sides equal each other, 4a+2=4a+2
Sorry 4a + 8 = 4a + 8
This is a true statement which implies all real numbers
thank you both :)
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Your welcome :D
awww I didn't get medaled :(
Here u go...
You actually answered first anyway
aww thanks!!
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