Question

Is this correct?

Answer 1

You are using the quadratic equation, do you know of it?

Answer 2

Quadratic formula gives us\[x = \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 3

So you want to set up your equation in \[ax^2+bx+c = 0\]

And from there it's basically plug and chug :)