Question

sint - 1/ cost = cost - cott/costcott

Answer 1

proof?

Answer 2

yes

Answer 3

can u attach the pic ..i think Q is not right

Answer 4

sin t - 1 = cos t - cot t
------ ----------
cos t cos t . cot t


taking RHS

=> cos t - cos t
-----
sin t
------------
cos t . cos t
----
sin t


=> taking LCM for numerator , we get

=> cos t . sin t -cos t
----------------
sin t
------------------------
cos t . cos t
----------
sin t


=> cancel sin t with sin t , we get

cos t . sin t -cos t
------------------------
cos t . cos t

=> taking cos t common in numerator

cos t ( sin t - 1 )
-----------------
cos t . cot t

=> cancelling cos t with cost t

=> we get sin t - 1
-------- == LHS
cot t


hence proved......... :-)