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Mathematics 19 Online
OpenStudy (quickstudent):

Correct?

OpenStudy (quickstudent):

OpenStudy (quickstudent):

@Ahaanomegas

OpenStudy (anonymous):

No, but close! You have \[ x = \frac {b \pm \sqrt{b^2-4ac}}{2a}. \]You want \[ x = \frac {-b \pm \sqrt{b^2-4ac}}{2a}. \]

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