Question

What is the end behavior of f(x) = 2.7^x – 3?

As x decreases without bound, f(x) decreases without bound.
As x increases without bound, f(x) approaches the line y = –3.

As x decreases without bound, f(x) increases without bound.
As x increases without bound, f(x) approaches the line y = –3.

As x decreases without bound, f(x) approaches the line y = –3.
As x increases without bound, f(x) decreases without bound.

As x decreases without bound, f(x) approaches the line y = –3.
As x increases without bound, f(x) increases without bound.

Answer 1

@hartnn @Haichi @ganeshie8 @satellite73 @Ashleyisakitty

Answer 2

Not sure So vEry sorry

Answer 3

That's okay, thanks for trying!

Answer 4

as x increases so does y
as goes to minus infinity , this sucker goes to zero

Answer 5

oh no the minus 3 is out at the end, so it goes to -3

Answer 6

@satellite73 D?

Answer 7

@geerky42 @ganeshie8 @satellite73 @iambatman @Kainui @undeadknight26

Answer 8

see
https://www.desmos.com/calculator/dwuknbmzvu

Answer 9

Am I right?

Answer 10

yes

x increase ---> y increase
x decrease ---> y approaches -3