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Write the following in their simplest form, involving only one trigonometric function: tanA/sec^2A -2
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\[\frac{ \tan \theta }{ \sec ^2\theta-2 }\]
\[\large={\sin A \over \cos A} \times{1\over {1\over \cos^2A}-2}\]
\[={\sin A \over \cos A} \times{\cos^2 A \over 1-2\cos^2 A}\]
\[={\sin A \times \cos A \over 1-2\cos^2 A}\]
next using the identities: \[\sin(2x)=2\sin x \cdot \cos x\]\[\cos(2x)=2\cos^2x-1\] we get:\[\large{={\frac12\sin \left( 2A \right)\over -\left( \cos \left( 2A \right) \right)}\\=\color{green}{-\frac12\tan \left( 2A \right)}}\]
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