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OpenStudy (anonymous):
\sqrt (1+cos2x)dx
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OpenStudy (hysenberg):
\[\sqrt{1+\cos2x}=\sqrt{\sin^2x+\cos^2x+\cos^2x-\sin^2x}=\sqrt{2}*cosx\]
OpenStudy (anonymous):
$$\int _{0}^{\pi} \sqrt {1+cos2x}$$
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