Question

Find the real solutions of the equation by graphing.

-19x^3-12x^2+16x=0

Answer 1

@texaschic101 could you possibly help me out/

Answer 2

-1.286,0,.655

Answer 3

thanks! could you help me with another?
@Vlery

Answer 4

sure thing btw if you're wondering how I got it I plotted it and looked where it crossed the x axis

Answer 5

I did the same but i made a mistake somewhere along the way!

Answer 6

https://www.desmos.com/calculator <-- that's bae

Answer 7

Find the real solutions of the equation by graphing.

-27=x^4-12x^2

Answer 8

the zeros are -3,-1.732,1.732,3

Answer 9

when you have that kinda of problem just move everything to one side
x^4-12x^2+27

Answer 10

right and are the other number besides -3 the square root of 3? and -3

Answer 11

yes

Answer 12

like would it be 3,-3, square root of 3, and square root of -3?

Answer 13

mathematically it's look like