Find the real solutions of the equation by graphing.

-19x^3-12x^2+16x=0

Question

Find the real solutions of the equation by graphing.

-19x^3-12x^2+16x=0

anonymous · Answer

@texaschic101 could you possibly help me out/

vlery · Answer

-1.286,0,.655

anonymous · Answer

thanks! could you help me with another?
@Vlery

vlery · Answer

sure thing btw if you're wondering how I got it I plotted it and looked where it crossed the x axis

anonymous · Answer

I did the same but i made a mistake somewhere along the way!

vlery · Answer

anonymous · Answer

Find the real solutions of the equation by graphing.

-27=x^4-12x^2

vlery · Answer

the zeros are -3,-1.732,1.732,3

vlery · Answer

when you have that kinda of problem just move everything to one side
x^4-12x^2+27

anonymous · Answer

right and are the other number besides -3 the square root of 3? and -3

vlery · Answer

yes

anonymous · Answer

like would it be 3,-3, square root of 3, and square root of -3?

vlery · Answer

mathematically it's look like |dw:1415377331021:dw|