Question

need to write this complex number in to rectangular form.
6(cos3pi/2+i sin3pi/2)

Answer 1

that number is in the form

\[\Large r*( \cos(\theta) + i*\sin(\theta) )\]

Answer 2

to convert to rectangular or cartesian form, you need to find x and y

the good news is that you can use these formulas

\[\Large x = r*\cos(\theta)\]
\[\Large y = r*\sin(\theta)\]

Answer 3

all you need to do is evaluate your expression

Answer 4

what is cos (3pi/2)

Answer 5

oh true, you could also express it in a+bi form

Answer 6

cos(3pi/2) = 0
sin(3pi/2) = -1

6( 0 + i*-1) = 0 -6i

Answer 7

thank you guys so much, Jim i found your example on algebra.com that helped me out tremendously

Answer 8

I'm glad it helped

Answer 9

what example on algebra.com?

Answer 10

http://www.algebra.com/algebra/homework/complex/Complex_Numbers.faq.question.88097.html