Question

Suppose we roll a six-sided die three times in succession, generating a sequence of three integers from the range 1-6. What is the probability that at least one of the rolls as a 6?

Answer 1

compute the probability that none are six, namely \(\left(\frac{5}{6}\right)^3\) and subtract that from 1

Answer 2

Ahh...that method is one I just read about... so .421 is what I get.
thank you