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Solve the following system of equations. 3x + 2y - 5 = 0 x = y + 10
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since the second equation is already arranged in terms of x you can just plug it in equation 1 and solve for y here's what i mean: 3x + 2y - 5 = 0 -> eqn 1 x = y + 10 -> eqn 2 sub eqn2 in eqn 1 3( y + 10 ) + 2y - 5 = 0 now can you solve for y?
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