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end behavior question
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end behavior of y=(x^4-2x^3+x^2)/(3x^3-9x^2+6x)?
@asnaseer
for large x, the highest power terms dominate
so in the numerator you have x^4, and in the denominator you have 3x^3
yea
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for large x y ~ x^4 / (3x^3 ) = x/3 after canceling so the end behavior, as x->oo , y -> oo , and as x-> -oo, y -> -oo
|dw:1415556847148:dw|
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