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(BEST ANSWER GETS MEDAL!) Please help! : ) If h(x) = {(2,1),(1,-3),(5,0),(-2,3)} and f(x) = 3x^2+2, evaluate (h of f)(1)
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f(1)= 3(1^2)+2=3+2=5 now (h of f)(x)=h(f(x)) therefore (h of f)(1)=h(f(1))=h(5)=0
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