Question

find all the zeros by factoring the function
F(x)=X^3+8

Answer 1

8=2^3

and we know that:
a^3+b^3=(a+b)(a^2-ab+b^2)

Answer 2

So,
x^3 + 2^3 = ...
can you expand it?

Answer 3

x*x*x*2*2*2?

Answer 4

a^3+b^3=(a+b)(a^2-ab+b^2)
x^3+2^3=(x+2)(x^2-2x+4)

Answer 5

see?

Answer 6

yea. ok thank you.....again :)