Question

Solve the equation. 7x^4-33x^2+26=0 Please!! :)

Answer 1

let x^2 = t
now 7t^2 - 33 t + 26 = 0

one root you get as 1 other = 26/7
which are values for t = x^2
now x ^2 = 1 and 26 /7
x = +1,-1, \[+\sqrt{26/7} ,, and -\sqrt{26/7}\]

which are answers to this equation