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Mathematics 7 Online
OpenStudy (anonymous):

PLEASE HELP ME

OpenStudy (anonymous):

sammixboo (sammixboo):

:) I am here to help

sammixboo (sammixboo):

Let's find out the voltages for the 30-watt bulb :) Since the 30-watt bulb has a power of 30, that is our P So P = 30 And with the 30-watt bulb the resistance is 140 ohms. So R = 140 \(\sqrt{P \times R}\) Plug the information P = 30, and R = 140 into the equation above. \(\sqrt{P \times R}\) \(\sqrt{30 \times 140}\) Now we have to find the product of P x R What is 30 x 140?

OpenStudy (anonymous):

4200

sammixboo (sammixboo):

Good now we have \(\sqrt{4,200}\) So do you know the square root of 4200?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

i will try

OpenStudy (nirmalnema):

sammixboo (sammixboo):

Okay hun tell me what you got =) Round to the nearest tenths if needed

OpenStudy (anonymous):

47

sammixboo (sammixboo):

Ah the square root of 4,200 ins't 47 :)

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