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Check with logarithims please
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\[\ln (\frac{ e^3 }{xy })\] write as a sum and/or difference of logarithms without exponents . be -3 - ln(x)+ln(y)?
\[\ln e^3-\ln(xy)\]
\[\ln=\log_e\]
when base and number are same thn log will give output as 1
that will be 3 only not -3
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ln e^3=3
ln(xy)=lnx +lny
Alright
3-(lnx+lny)
3- ln(x)-ln(y)?
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yeah
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