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OpenStudy (anonymous):
Ok i was wondering if you guys could tell me whether my answers are right or wrong
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OpenStudy (anonymous):
OpenStudy (anonymous):
@StudyGurl14
OpenStudy (studygurl14):
\(\large\tt \#1:\color{red}{incorrect}\)
\(\large 4\sqrt{2}+7\sqrt{2}-3\sqrt{2}=(4+7-3)\sqrt{2}=8\sqrt{2}\)
OpenStudy (studygurl14):
\(\large\tt\#2:\color{green}{correct}\)
OpenStudy (studygurl14):
\(\large\tt\#3:\color{red}{incorrect}\)
\(\large 7\sqrt{3}-4\sqrt{6}+\sqrt{48}-\sqrt{54}\rightarrow 7\sqrt{3}-4\sqrt{6}+\sqrt{16\times3}-\sqrt{9\times6}\)
\(\large\rightarrow 7\sqrt{3}-4\sqrt{6}+4\sqrt{3}-3\sqrt{6}\rightarrow 11\sqrt{3}-7\sqrt{6}\)
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OpenStudy (anonymous):
@StudyGurl14
OpenStudy (studygurl14):
\(\large \sqrt{3}(\sqrt{21})\rightarrow\sqrt{63}\rightarrow\sqrt{9\times7}\rightarrow 3\sqrt{7}\)
OpenStudy (studygurl14):
^ for #4
OpenStudy (studygurl14):
\(\large\tt\#5:\color{red}{incorrect}\)
\(\large\sqrt{5}(10-4\sqrt{2})\rightarrow 10\sqrt{5}-4\sqrt{20}\)
none of the above
OpenStudy (studygurl14):
\(\large\tt\#6:\color{red}{incorrect}\)
\(\large 2\sqrt{3}-2\sqrt{3}=0\)
0 is rational
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OpenStudy (studygurl14):
\(\large\tt\#7:\color{green}{correct}\)
OpenStudy (studygurl14):
\(\large\tt\#8:\color{green}{correct}\)
OpenStudy (studygurl14):
\(\large\tt\#8:\color{red}{incorrect}\)
\(\large\sqrt{2}(5+\sqrt{8})\rightarrow 5\sqrt{2}+\sqrt{16}\rightarrow4+5\sqrt{2}\)
OpenStudy (studygurl14):
@AsapHershey
OpenStudy (anonymous):
@StudyGurl14
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OpenStudy (studygurl14):
sorry, i meant #9 for the last one
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