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The square of a number is equal to 10 less than 7 times that number. What are the two possible solutions?

Which of the following equations is used in the process of solving this problem?

x2 - 7x + 70 = 0

x2 - 7x + 10 = 0

x2 + 7x - 10 = 0

Question

Help whenever you can
The square of a number is equal to 10 less than 7 times that number. What are the two possible solutions? 

Which of the following equations is used in the process of solving this problem?



x2 - 7x + 70 = 0

x2 - 7x + 10 = 0

x2 + 7x - 10 = 0

anonymous · Answer

The 2nd equation is used for this question.

anonymous · Answer

Can you explain to me how you got that @AGray7 ?

anonymous · Answer

So you know that x^2= 7x-10
Then by moving everything to one side of the equation, you get x^2-7x+10=0
Does that help?

anonymous · Answer

Yes A lot! thank you so much! @AGray7