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OpenStudy (sleepyjess):
@bibby
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OpenStudy (sleepyjess):
Choose the graph of y = \(\dfrac{2}{3}sin \dfrac{1}{2}x\)
OpenStudy (sleepyjess):
i think it is the last one on the first screenshot
OpenStudy (bibby):
the wavelength is \(-2\pi->2\pi\)
wolfram says the graph looks likes this
http://puu.sh/cLKfy.png
OpenStudy (bibby):
that means it is compressed by a factor of 2/3 so it goes from x=-0.67 to 0.67
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OpenStudy (sleepyjess):
how are you so good at this???
OpenStudy (bibby):
I'm not lol, I'm just matching. it's like when you were in kindergarten and you saw the red square and the red squares hole and you put the shape in
OpenStudy (bibby):
anyhow I think it'd be the first one in the f irst link
OpenStudy (sleepyjess):
do you want me to post the other 2 here or open a new question?
OpenStudy (bibby):
I don't care about medals
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OpenStudy (sleepyjess):
Find the amplitude of y = -2 sin x.
-2π
2π
2 \(\leftarrow\) this one?
\(\dfrac{\pi}{2}\)
OpenStudy (sleepyjess):
if you see question marks after -2 and 2 it is supposed to be pi
OpenStudy (bibby):
i think you can see it if you refresh
OpenStudy (sleepyjess):
i am pretty sure that one is right though
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