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Can you please help me solve question 23?
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\[(2,0),(3,-2),(1,-2)\] too bad cause @amistre64 has a snappy way of doing this not me just grind it til you find it \[ax^2+bx+c\] and get three equations with three unknowns
\[4a+2b+c=0\] is one of them
\[9a+3b+c=-2\] is another and \[a+b+c=-2\] is the third
I have that. where do i go from there?
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