Question

square root 4x+5=x
solving radical equations
Help!

Answer 1

\[\sqrt{4x +5}=x\]
Is this it?

Answer 2

\[(\sqrt{4x+5})^{2}= x ^{2}\]
\[4x + 5 = x ^{2}\]
\[x ^{2}-4x - 5 =0\]
\[(x -5)(x +1) = 0\]
x = 5, x =-1

Answer 3

\[\sqrt{4(5) + 5}= 5\]