Question

sec^3x-cos^3x/secx-cosx=sec^2x+1+cos^2x
does anyone know how to prove this?

Answer 1

Put parentheses please so we know what is your exact question?

Answer 2

Use the formula for
\[
a^3-b^3=(a-b) \left(a^2+a b+b^2\right)
\]

Answer 3

Apply the above formula to get
\[
\sec ^3(x)-\cos ^3(x)=(\sec (x)-\cos (x)) \left(\sec ^2(x)+\cos
(x) \sec (x)+\cos^2(x)\right)\]

You should be able to finish it now

Answer 4

What is this product \(\cos(x) \sec(x)\) equal to?
Can you show that it is equal to 1