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Mathematics 61 Online
OpenStudy (anonymous):

Solve |5x-3| ≤8 then graph the solution on a number line. Please show work

OpenStudy (anonymous):

How about you tell us what your problem is. Im not going to do your work for you.

OpenStudy (anonymous):

well i have an answer i just want to make sure it is right, and I am confused on how to graph it

OpenStudy (anonymous):

So when you see an absolute value sign you automatically know that the graph should look like what?

OpenStudy (anonymous):

That's the part I am confused on

OpenStudy (anonymous):

If you solve it and get an answer i will give you a medal and fan you

OpenStudy (anonymous):

Absolute value means the distance away from 0

OpenStudy (anonymous):

Correct?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

So, you can be -5 units away from something, but truly you are still 5 units away from where that something is.

OpenStudy (anonymous):

Give me a minute to type this up

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

To solve this equation we know that the value of 5x-3 is always 8 units away from 0. This is kind of hard to explain here, but this is what it actually means: \[8\le5x -3\le8\]

OpenStudy (anonymous):

However, that is for a number line graph and I'm assuming you want an actual graph

OpenStudy (anonymous):

a number line

OpenStudy (anonymous):

You want a number line?

OpenStudy (anonymous):

yes graph the solution on a number line

OpenStudy (anonymous):

|dw:1415749182948:dw|

OpenStudy (anonymous):

can you please solve the problem

OpenStudy (anonymous):

As stated above, 5x-3 is less than 8 but greater than -8 Im about to finish the drawing

OpenStudy (anonymous):

|dw:1415749342868:dw| This basically is saying that 5x-3 can be anywhere in the shaded area.

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