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A population of n fish exists within a lake. The fish population is increasing at a rate of 2% a month. Write a formula that tells us the number of fish present after time t. b) find the number of fish present after 2 years, if the original fish population is 2200 (round to the nearest fish). c) after 10 years, fishermen discover the lake and begin killing scores of the fish. Fishermen are killing off 3.5% of the stock each month. when will the fish be extinct from the lake? Remember the fish are still reproducing at 2% a month.
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let t = # months y = A * ( 1 + .02) ^ t , where A = # of fish at time zero
@perl Thanks, do you know how to do part c)?
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