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Given h(x) = 3x/-x-1 find h^-1(x)
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h^-1 is the inverse of the function
So what does that mean?
You have not done inverse functions?
I have, this is just a review problem from last year. Do you set -1 for x?
You make h(x) =y. So you have y=3x/(-x-1)...then switch x and y so you then have x= 3y/-y-1)...now solve for y.
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x=3y/(-y-1) now solve for y
I'm lost here. Do you multiply x times (y-1)?
is x = to 3y^2?
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