Question

Differential Equation

Answer 1

$$\frac{dy}{dx}=(x+y-1)+\frac{x+y}{log(x+y)}$$

solution: $$(1+log(x+y)-log{(1+log(x+y))=x+C}$$

Answer 2

I did this

Answer 3

@midhun.madhu1987

Answer 4

Your're missing it: If \(t=x+y\), then \(\dfrac{dt}{dx}=1+\dfrac{dy}{dx}\).

Answer 5

Or not... I might be mistaken!

Answer 6

Right I see that now. Thanks