Consider an assembly line with 20 stations. Each station has a 0.5% probability of making a defect. At the end of the line, an inspection step singles out the defective units. The inspection step catches 80% of all defects. From inspection, units that are deemed to be non defective are
moved to the shipping department.
Q::What is the liklihood that a unit ends up in a rework?

Question

Consider  an  assembly  line  with  20  stations.  Each  station  has  a  0.5%  probability  of  making  a  defect.  At  the  end  of  the  line,  an  inspection  step  singles  out  the  defective  units.  The  inspection  step  catches  80%  of  all  defects.  From  inspection,  units  that  are  deemed  to  be  non defective  are  
moved  to  the  shipping  department.
Q::What is the liklihood that a unit ends up in a rework?

anonymous · Answer

u afk?

kropot72 · Answer

Let the event 'a defective unit is made' be D, and let the event 'a defective unit is detected' be F.
P(D) = 0.005
P(F) = 0.8
$$\large P(D \cap F)=0.005\times0.8=you\ can\ calculate$$
Hint: If the likelihood is required as a percentage, multiply the result of the calculation by 100.

anonymous · Answer

What is the answer?

kropot72 · Answer

What is the result of your calculation?