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AP GP help @ganeshie8
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If the quadratic equation \[ax ^{2}-2bx+c=0\] has two equal roots, which of the following are true?
1: both roots are b/a 2: a,b,c are GP 3. a,b,c are AP
Discriminant has to be 0 for a quadratic to have equal roots
find the discriminant of given equation and set it equal to 0
2b^2-4ac = 0????
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(2b)^2 - 4ac = 0
cancel 4, you get b^2 - ac = 0 b^2 = ac b = sqrt(ac) that means b is the geometric mean of a and c
that also means a, b, c are in GP
um what about the roots
yes both roots will be b/a
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thaks
b/c when D = 0, quadratic formula gives : \[x = \dfrac{2b \pm 0}{2a} \]
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