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solving radical equations ^4 square root x-7=2 heeelp!
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\[\sqrt[4]{x-7=2}\]
the answer is 3
the square root of 9 which is what x-7=2 = so the square root of 9 is 3
what is the process?
cant be 3
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look carefully its not the square root but the 4th root
is the 2 also under the root sign?
I don't know how do this
@midhun.madhu1987 do you know this?
Question unclear... = cannot be inside square root
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both side power of 4th
x-7=2^4
x=16-7=9
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