solve the equation for exact solutions over the interval [0,2pi).
(cscx+2)(cscx-√2)=0

Question

solve the equation for exact solutions over the interval [0,2pi).
(cscx+2)(cscx-√2)=0

anonymous · Answer

Id love to help but i do not know this stuff. Sorry!

campbell_st · Answer

well the equation has been factored for you.. and csc(x) = 1/sin(x) 

so making the substitution you need to solve 

1/sin(x) + 2 = 0

so 

1/sin(x) = -2

take the reciprocal 

sin(x) = -1/2 

similar for the other factor

you will have 2 exact values... and you can find them in the given domain. 

hope it helps

anonymous · Answer

it does thank you... the square root over 2 was just stumping me

anonymous · Answer

pi/4 and pi/6  ??