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Precalculus
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prove cosx/1+sinx=1-sinx/cosx
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cosx/(1-sinx) = (1+sinx)/cosx =cosx/(1-sinx) =(cosx(1+sinx))/((1-sinx)(1+sinx)) =(cosx+cosxsinx)/(1-sin²x) =(cosx+cosxsinx)/(cos²x) =(1+sinx)/cosx
\[{\cos x \over1+\sin x}={1-\sin x \over \cos x}\]
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\[LHS\\={\cos x \over 1+ \sin x}\\={\cos x \over 1+ \sin x}\times {\left( 1-\sin x \right)\over\left( 1-\sin x \right)}\]
\[={\cos x\left( 1-\sin x \right)\over 1-\sin^2x}\]
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\[={\cos x\left( 1-\sin x \right)\over \cos^2x} \\={1-\sin x \over \cos x}\\=RHS\]
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