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Mathematics 12 Online
OpenStudy (anonymous):

max value of ....

OpenStudy (anonymous):

\[\huge asin^2x +b \cos^2x \]

OpenStudy (anonymous):

a+b

OpenStudy (anonymous):

yeah for -1

OpenStudy (anonymous):

i am not able to think properly today sorry

OpenStudy (anonymous):

huh? what for -1?

OpenStudy (ikram002p):

a=b then maximum =a itself a>b then maximum =b :) thus u can say maximum =max (a,b)

OpenStudy (ikram002p):

i made a typo , third line max=a :)

OpenStudy (anonymous):

Actually there is a different question i will post it new

OpenStudy (ikram002p):

:)

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