Question

Find the standard form of the equation of the parabola with a focus at (-4, 0) and a directrix at x = 4.
Answers:
y^2 = -8x
16y = x^2
y = -1/16 x^2
x = -1/16 y^2

Answer 1

@ant501 help on this one?

Answer 2

sure

Answer 3

c

Answer 4

Thanks lol another one?

Answer 5

sure

Answer 6

@ant501
Find the vertex, focus, directrix, and focal width of the parabola.

x = 3y^2
The answers are:
vertex:(0,0) focus (1/12, 0) directrix: x = 1/12 focal width: 12
vertex (0,0) focus (1/12, 0) directrix: x = -1/12 focal with: 0.33
vertex (0,0) focus (0, 1/16) directrix x = -1/16 focal width: 0.33
vertex (0,0) focus (1/16, 0) directrix y = -1/16 focal width: 12

Answer 7

c

Answer 8

i mean b

Answer 9

That's the one I thought it was. One final one? I'll post a new question so I can give you more medals for the help. @ant501

Answer 10

sure