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\[\large 2\sqrt[3]{108}\] What are the factors of 108?
1,2,3,4,6,9,12,18,27,36,54,108
The cube root of one of those factors is an integer. Can you find that factor?
27?
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Correct. 4 * 27 = 108. Now we can take 27 outside the radical sign, remembering to take its cube root as we do. Can you do that?
\[3\sqrt[3]{4}\]
I would multiply 3 by 2 and get D, right?
Correct. Good work!
Thank you! :D
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You're welcome :)
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