two kinds of nuts are mixed to sell at 70 cents per bag. one kind sells at 50 cents per bag; the other at 80 cents per bag. How much of each kind should be used in 300 bags of the mixture? (use 2 variables to solve)

Question

anonymous · Answer

@amistre64  heree's what i dod.

x= amt of bagsfor 1st kind
y= amt of bags for 2nd kind

50x+20y= 70(x+y)
x+y=300

anonymous · Answer

do i use number of nuts or bags? o.o

anonymous · Answer

i think i got first equation right, but i don't wknow what to set it equal to

anonymous · Answer

oh wait, i need a variable for total amt.

amistre64 · Answer

two kinds of nuts are mixed to sell at 70 cents per bag. 

one kind sells at 50 cents per bag; 
  50x

the other at 80 cents per bag. 
   80y

How much of each kind should be used in 300 bags of the mixture? 
x+y = 300

so:  50x + 80y = 70(300)

does this seem right?

anonymous · Answer

ahh it makes sense now with the 70 cents per bag times 300. ty once again!

amistre64 · Answer

youre welcome