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HippoCampus Calculus & Advanced Math 15 Online
OpenStudy (anonymous):

what is the derivative of y=(1/sinx) ?

OpenStudy (anonymous):

y=(1/sinx) y' =(-cosx/(sinx)(sinx)) = -cotx / sinx = -cotx cscx

OpenStudy (er.mohd.amir):

its y=cosec x so y' =- cosec x . cot x

jaynator495 (jaynator495):

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