Ask your own question, for FREE!
Algebra 19 Online
OpenStudy (anonymous):

Solve for 0

OpenStudy (ahsome):

\(0<x<2\pi\) \(2*cos^{2x}=cosx\) Right?

OpenStudy (anonymous):

Yes but the x in cos^2 x is not an exponent

OpenStudy (anonymous):

@whpalmer4

OpenStudy (anonymous):

@Ahsome

OpenStudy (ahsome):

Oh, OK

OpenStudy (anonymous):

\[2\cos ^{2}(x)=\cos (x)\]

OpenStudy (anonymous):

divid be cos

OpenStudy (anonymous):

\[2\cos (x)=1\]

OpenStudy (anonymous):

\[\cos (x)=\frac{ 1 }{ 2 }\]

OpenStudy (anonymous):

\[x=\cos^{-1} \frac{ 1 }{ 2 }\]

OpenStudy (anonymous):

x=60 deg

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!