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What is the exact value of cos(2 sin^-1 (1/3))
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\(sin^{-1}(1/3)=?\)
well don't you have to draw a triangle? |dw:1415930236601:dw|
so 1^2 + b^2 = 3^2 so b=2sqrt2
then?? that is the side, not the angle.
|dw:1415930424556:dw|
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you don't need to find the angle
ok thats what i thought
:)
\[\cos(2\theta)=\cos^2(\theta)-\sin^2(\theta)\]
then use your triangle
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and that is a trig identity?
of a double angle
yes it is a trig identity
thanks
can you get the answer now?
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yup it is 7/9
thank you so much
good
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