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Mathematics 21 Online
OpenStudy (anonymous):

3/2y=16/y+2

OpenStudy (johnweldon1993):

\[\large \frac{3}{2y} = \frac{16}{y + 2}\] like that right?

OpenStudy (johnweldon1993):

If so, we need merely cross multiply so this becomes \[\large 3(y + 2) = 16(2y)\] and simplify from there by distributing etc...

OpenStudy (anonymous):

oh ok

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