Need to find bounds for a double polar integral. HALP.

Find the area of the surface which is the portion of the cone z = 2sqrt(x^2 + y^2) inside the cylinder x^2 + y^2 = 4.

Question

Need to find bounds for a double polar integral. HALP.

Find the area of the surface which is the portion of the cone z = 2sqrt(x^2 + y^2) inside the cylinder x^2 + y^2 = 4.

anonymous · Answer

Is this correct? 
$$\int\limits_{0}^{2\pi} \int\limits_{0}^{2} 2r^2 dr d theta$$

johnweldon1993 · Answer

I believe that is correct...you have the cylinder with radius 2 so 0 to 2 and you are integrating over the full area so 0 to 2pi is correct

anonymous · Answer

excellent!