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Mathematics 8 Online
OpenStudy (anonymous):

when factored completely, the expression 3x^3-5x^2-48x+80 is equivalent to

OpenStudy (campbell_st):

well you can group in pairs for this expression (3x^3 - 5x^2) - (48x - 80) fractor each pair and you get x^2(3x - 5) - 16(3x -5) so I'll let you continue to factor the expression

OpenStudy (secret-ninja):

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