Question

B^2+5b-35=3b

Answer 1

start by rewriting, subtract 3b from both sides

\[b^2 + 2b - 35 = 0\]

now find the factors of -35 that add to 2... the larger factor is positive...

what do you think..?

Answer 2

I just don't know how to do it at all ..

Answer 3

ok... so the equation can be solved for b by factoring...

the factors of -35 you need are 7 and -5

so in factored form its

(b + 7)(b - 5) = 0

so that means to find the solutions you need to solve

b + 7 = 0

and

b - 5 = 0

if either factor is zero then the whole equation is zero

so find the values of b..