Question

What is the best way to classify each equation?
Column A Column B
1.http://static.k12.com/bank_packages/files/media/mathml_44224350532a4c3c2c3ab76c91b56c0e9a3d3fbd_1.gif

2.http://static.k12.com/bank_packages/files/media/mathml_67dbe0f8ac13d18075ad591e3eba2f9baae2cd6d_1.gif

3.http://static.k12.com/bank_packages/files/media/mathml_97b7aabdbab6af8b0fa64673a9dafdf116c62818_1.gif

4.http://static.k12.com/bank_packages/files/media/mathml_571f02f9f02a4a28eed8c9844c8207c5769da0bc_1.gif

A.
identity
B.
contradiction
C.
neither

Answer 1

@thomaster

Answer 2

C

Answer 3

C

Answer 4

C

Answer 5

C

Answer 6

C

Answer 7

C

Answer 8

C

Answer 9

C

Answer 10

C

Answer 11

C

Answer 12

aye theres 4 problems c is for which one

Answer 13

@iGreen

Answer 14

@Kit_Kat_Nat_<3 @Abhisar @AnswerMyQuestions @AMYCARTER @mathmath333

Answer 15

\(\large\tt \begin{align} \color{black}{5x-20=2(3x-10)\\
5x-20=6x-20\\
}\end{align}\)
this eqn will be true for \(\Large x=0 \) so it is neither identity
nor contradiction

Answer 16

can u help me with the rest please

Answer 17

\(\large\tt \begin{align} \color{black}{4x-16-2x=2(x-8)\\
2x-16=2x-16\\}\end{align}\)

this is clear identity

Answer 18

\(\large\tt \begin{align} \color{black}{6x-15=3(2x-6)\\
6x-15=6x-18\\
-15\neq -18
}\end{align}\)

this contradiction

Answer 19

D

Answer 20

try the 4th

Answer 21

kk one sec

Answer 22

Simplifying
5x + -3(x + -4) = 2(x + -6)

Reorder the terms:
5x + -3(-4 + x) = 2(x + -6)
5x + (-4 * -3 + x * -3) = 2(x + -6)
5x + (12 + -3x) = 2(x + -6)

Reorder the terms:
12 + 5x + -3x = 2(x + -6)

Combine like terms: 5x + -3x = 2x
12 + 2x = 2(x + -6)

Reorder the terms:
12 + 2x = 2(-6 + x)
12 + 2x = (-6 * 2 + x * 2)
12 + 2x = (-12 + 2x)

Add '-2x' to each side of the equation.
12 + 2x + -2x = -12 + 2x + -2x

Combine like terms: 2x + -2x = 0
12 + 0 = -12 + 2x + -2x
12 = -12 + 2x + -2x

Combine like terms: 2x + -2x = 0
12 = -12 + 0
12 = -12

Solving
12 = -12

Answer 23

is this right?

Answer 24

yes good but

Answer 25

\(\Large\tt \begin{align} \color{black}{12\neq -12
}\end{align}\)

Answer 26

neither? right?

Answer 27

wait no its a or b

Answer 28

no such type of statement\(\huge (x\neq y )\) are called \(\huge contradiction\)

Answer 29

ohhh i see

Answer 30

thanx man