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1) http://gyazo.com/8596835e80dadfc46eba5e1ac777b33c 2) http://gyazo.com/e4bbb9f6ebd2b6fc2ee38905c1137a8d @nincompoop
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@Abhisar
You will get the answer sooner by placing this question in Physics. 1. The formula of kinetic energy is \(E_K=\frac{1}{2}mV^2\). So if they have the same speed, the train's \(E_K\) will be greater than the car's. 2. Apply the formula of kinetic energy is \(E_K=\frac{1}{2}mV^2\). You will see that the train's \(E_K\) is less than the car's \(K_E\).
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