Question

+1 Medal! Please Explain!

1) http://gyazo.com/8596835e80dadfc46eba5e1ac777b33c

2) http://gyazo.com/e4bbb9f6ebd2b6fc2ee38905c1137a8d

Answer 1

2.
\[kenergy = 1/2 *(m)*(v^2)\]
Find kinetic energy for both train and car
then compare(find ratio) between them

Answer 2

Nvm, I just did the math. 4) A

Answer 3

1.
\[kenergy = (1/2)*(m)*(v^2)\]
\[kenergy_{train}/ kenergy_{car} = m_1/m_2\]

Answer 4

yups